[Mristudio-users] Applying Hmap and Kimap

[Xin Li]

Kimap and Hmap gives the changes of the coordinates after transformation. Hmap is reciprocal to Kimap. For example, the first three values of your Kimap tells that the coordinate(0,0,0) in the transformed subject image corresponds to the coordinate(7.800029524490799, 0.000000000022612, 0.000001498922010) in the original subject image. The second three values tells that the coordinate(1.0,0,0) in the transformed subject image corresponds to the coordinate(0.000000000000000, 0.000001839432419, 0.000000000000000) in the original subject image.



Xin



----- Original Message -----
From: Jeff Sadino <jsadino.queens at gmail.com>
Date: Tuesday, April 5, 2011 10:03 pm
Subject: [Mristudio-users] Applying Hmap and Kimap
To: "DTI Studio, ROI Editor, DiffeoMap Questions/Support" <mristudio-users at mristudio.org>


> Hello,
>  
>  I was reading a post from February 2010 titled "apply transformation 
> to
>  landmarkers & command file" and wanted to ask one more question about 
> it.
>   The poster is asking how to apply the Kimap outside of DiffeoMap, mainly
>  Matlab.  Can someone please explain to me the format of the Kimap and 
> Hmap
>  Transformations?  What do you guys mean when you say Vector (x, y, z)
>  x X-dimension
>  x Y-dimension x Z-dimension?  When I loaded up my Kimap into matlab 
> as a
>  binary file, the first six values after the header were:
>  
>    1.0e+031 *
>  
>     7.800029524490799
>     0.000000000022612
>     0.000001498922010
>     0.000000000000000
>     0.000001839432419
>     0.000000000000000
>  
>  My image was 181 x 217 x 181.  Thank you very much,
>  Jeff Sadino
>  
>  The original post is below:
>  
>  1. One thing I need to note is that the transformation matrix I have 
> is
>  a "final" combined matrix of AIR rigid, AIR affine, and LDDMM K map 
> (so it
>  should be in the raw data format). Can I extract the "vector" 
> information at
>  the specified location in this transformation matrix? And how?
>  
>  Hello Yi,
>  
>  As Susumu said, transformation matrices contain vectors at each coordinate,
>  indicating where is the new location. The structure is Vector (x, y, 
> z) x
>  X-dimension x Y-dimension x Z-dimension. You may write matlab code to
>  extract the vector information. 
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